0.05x^2-x-480=0

Solution for 0.05x^2-x-480=0 equation:

0.05x^2-x-480=0

We add all the numbers together, and all the variables

0.05x^2-1x-480=0

a = 0.05; b = -1; c = -480;
Δ = b2-4ac
Δ = -12-4·0.05·(-480)
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{97}}{2*0.05}=\frac{1-\sqrt{97}}{0.1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{97}}{2*0.05}=\frac{1+\sqrt{97}}{0.1}
$